Definite IntegrationHard

Question

The value of $\int_{- \frac{\pi}{2}}^{\frac{\pi}{2}}\mspace{2mu}\left( \frac{1}{\lbrack x\rbrack + 4} \right)dx$, where [•] denotes the greatest integer function, is

Options

A.$\frac{1}{60}(21\pi - 1)$
B.$\frac{1}{60}(\pi - 7)$
C.$\frac{7}{60}(3\pi - 1)$
D.$\frac{7}{60}(\pi - 3)$

Solution

$I = \int_{- \pi/2}^{\pi/2}\mspace{2mu}\frac{1}{\lbrack x\rbrack + 4}dx$

$${I = \int_{- \pi/2}^{- 1}\mspace{2mu}\frac{dx}{2} + \int_{- 1}^{0}\mspace{2mu}\frac{dx}{3} + \int_{1}^{0}\mspace{2mu}\frac{dx}{4} + \int_{1}^{\pi/2}\mspace{2mu}\frac{dx}{5} }{= \frac{1}{2}\left( - 1 + \frac{\pi}{2} \right) + \frac{1}{3}(1) + \frac{1}{4}(1) + \left( \frac{\pi}{2} - 1 \right)\frac{1}{5} }{= \frac{7\pi}{20} - \frac{7}{60} = \frac{7}{60}(3\pi - 1)}$$

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