A body of mass 2 kg is moving along x -direction such that its displacement as function of time is g

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A body of mass 2 kg is moving along x -direction such that its displacement as function of time is given by $x(t) = \alpha t^{2} + \beta t + \gamma m$, where $\alpha = 1	ext{ }m/s^{2}$, $\beta = 1	ext{ }m/s$ and $\gamma = 1	ext{ }m$. The work done on the body during the time interval $t = 2	ext{ }s$ to $t = 3	ext{ }s$, is

Accepted Answer

$x(t) = t^{2} + t + 1$$${v(t) = 2t + 1 }{a(t) = 2 }$$$F = 4	ext{ }N$.Displacement $= x(3) - x(2)$$${= 13 - 7 = 6M }{W = F.S = 4 	imes 6 = 24	ext{ }J}$$

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