Quadratic EquationHard
Question
If the value of quadratic trinomial $ax^{2} - bx + c$ is an integer for $x = 0,x = 1$ and $x = 2$, then the valueof the given trinomial is an integer for
Options
A.$x = 2017$
B.$x = 2018$
C.$x = - 4$
D.$x = - 2017$
Solution
$f(x) = ax^{2} - bx + c$
$$\begin{matrix} & f(0) = c \in I \\ & f(1) = a - b + c = k_{1} \\ & f(2) = 4a - 2\text{ }b + c = k_{2} \end{matrix}\ k_{1},k_{2} \in I$$
$$\begin{matrix} a - b & \ \in I \\ 2a + 2(a - b) + c & \ = k_{2} \\ 2a & \ \in I\ \Rightarrow \ 2\text{ }b \in I \\ f(2k) & \ = 4ak - 2bk + c \in I \\ f(2k + 1) & \ = a(2k + 1)^{2} - b(2k + 1) + c = 4{ak}^{2} + 4ak + a - 2bk - b + c \\ & \ = 4{ak}^{2} + 4ak - 2bk + (a - b + c) \in I \\ \Rightarrow \ f(x) & \ \in I\forall x \in I \end{matrix}$$
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
The set of all real values of ' $a$ ' for which both the roots of the equation $x^{2} - 1 = 0$ lie between the roots of ...Let $\alpha$ and $\beta$ be the roots of equation $x^{2} + 2ax + (3a + 10) = 0$ such that $\alpha < 1 < \beta$. Th...If roots of the equation 3x2 + 2(a2 + 1) x + (a2 − 3a + 2) = 0 are of opposite signs, then a lies in the interval ...The adjoining figure shows the graph of y = ax2 + bx + c. Then -...If p and q are positive then the roots of the equation x2 − px − q = 0 are-...