Quadratic EquationHard
Question
The complete set of real values of 'a' for which the smaller root of the equation $x^{2} + 2ax - 3 = 0$ lies in the interval $( - 1,1)$ is
Options
A.$(1,\infty)$
B.$(0,1)$
C.$\left( - \frac{1}{4},\infty \right)$
D.$a \in (2,\infty)$
Solution
$$x - \frac{3}{x} = 2a$$
from graph it is clear that
$$2a > 2 \Rightarrow a > 1$$
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