Quadratic EquationHard
Question
The degree of the polynomial $p(x)$ which satisfies the condition $(x)p(x - 1) = (x - 15)p(x)$ is :
Options
A.4
B.15
C.7
D.can not be determined
Solution
$P(x) = ax(x - 1)(x - 2)\ldots\ldots(x - 14)$
Create a free account to view solution
View Solution FreeMore Quadratic Equation Questions
If the equation = 1 has roots equal in magnitude but opposite in sign, then the value of a + b is -...Let a, b, c be real numbers, a ≠ 0. If α is a root of a2x2 + bx + c = 0, β is the root of a2x2 - bx - c ...Number of solutions of equation (a + x)2/3 + (x − a)2/3 = 4 (a2 − x2)1/3 are -...Let $\lim_{x \rightarrow 2}\mspace{2mu}\frac{(tan(x - 2))\left( r^{2} + (p - 2)x - 2p \right)}{(x - 2)^{2}} = 5$ for som...For all real values of x, the maximum value of the expression is-...