Graph between $\log\left( \frac{x}{m} \right)$ and log P is a straight line at an angle 45° with int

Question

Graph between $\log\left( \frac{x}{m} \right)$ and log P is a straight line at an angle 45° with intercept on y-axis, 0.3010. The amount (in g) of the gas absorbed per g of the adsorbent when pressure is 0.2 atm is (assume that the adsorption obey Freundlich isotherm)

Accepted Answer

$\frac{x}{m} = K.P^{\frac{1}{n}} \Rightarrow \log\frac{x}{m} = \log K + \frac{1}{n}.\log P$

From question, log K = 0.3010 = log2 ⇒ K =2 and $\frac{1}{n} = \tan 45^{0} = 1 \Rightarrow n = 1$

$\therefore\frac{x}{m} = 2 \times P = 2 \times 0.2 = 0.4$

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