ThermodynamicsHard
Question
The vapour pressure of water is 0.04 atm at 27°C. The free energy change for the following process is H2O (g, 0.04 atm, 27°C) → H2O (l, 0.04 atm, 27°C)
Options
A.0
B.$R \times 300 \times \ln\frac{1}{25}$
C.R × 300 × ln 25
D.300R
Solution
At 0.04 atom, the system is in equilibrium.
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
During vapourisation of H2O(l) at 373 K & 1 atm...The increase of pressure on ice ⇋ water system at constant temperature will lead to :...The following reaction is at equilibrium at 298 K 2NO (g, 0.00001 bar) + Cl2 (g, 0.01 bar) $\rightleftharpoons$ 2NOCl (...If liquids A and B form an ideal solution...One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 L to 10 L. The change in internal...