ThermodynamicsHard
Question
The enthalpy and entropy change for a chemical reaction are −2500 cal and +7.4 cal/K, respectively. The nature of reaction at 298 K is
Options
A.spontaneous
B.reversible
C.never occurring
D.non-spontaneous
Solution
$\Delta G = \Delta H - T.\Delta S = ( - 2500) - 298 \times ( + 7.4) = - ve \Rightarrow \text{Spontaneous}$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
Each of the vessels 1 and 2 contain 1.2 moles of gaseous helium. The ratio of the volume of vessels is V2/V1 = 2.0, and ...ΔE must be zero for...A system is said to be in thermodynamic equilibrium with the surroundings, if...Among the following, the intensive property is (properties are)...One mole of an ideal gas at 300 K is expanded isothermally from an initial volume of 1 L to 10 L. The change in internal...