An ideal monoatomic gas undergoes a reversible process, where $\frac{P}{V}$ = constant, from (2 bar,

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An ideal monoatomic gas undergoes a reversible process, where $\frac{P}{V}$ = constant, from (2 bar, 273 K) to 4 bar. The value of $\frac{\Delta U}{w}$ for this process is

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$P.V^{- 1} = K \Rightarrow x = - 1$$	ext{Now, }\frac{\Delta U}{w} = \frac{n.C_{v,m}.\Delta T}{\left( \frac{n.R.\Delta T}{x - 1} ight)} = - 2.\frac{C_{v,m}}{R} = - 2 	imes \frac{\frac{3}{2}R}{R} = - 3$

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