ThermodynamicsHard
Question
An ideal gas undergoes a process in which its pressure and volume are related as PV n = constant, where n is a constant. The molar heat capacity for the gas in this process will be zero if
Options
A.n = $\gamma$
B.n = $\gamma$ – 1
C.n = $\gamma$ + 1
D.n = 1 – $\gamma$
Solution
$C_{m} = \frac{R}{\gamma - 1} + \frac{R}{1 - n} = 0 \Rightarrow \gamma - 1 = - (1 - n) \Rightarrow n = \gamma$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
The standard Gibbs energy change at 300 K for the reaction 2A ⇋ B + C is 2494.2J. At a given time, the composition...$20.0{dm}^{3}$ of an ideal gas ' X ' at 600 K and 0.5 MPa undergoes isothermal reversible expansion until pressure of th...Among the following, the intensive property is (properties are)...The normal boiling point of a liquid is 350 K and ΔHvap is 35 kJ/mol. Assume that ΔHvap is independent from temperature ...For an isolated system, the wall/boundary separating the system from surrounding must be...