ElectrochemistryHard
Question
The EMF of the cell: Zn−Hg (C1M)|Zn2+ (aq)|Zn−Hg (C2M) at 25°C, if the concentrations of the zinc amalgams are: C1 = 10 g per 100 g of mercury, C2 = 1 g per 100 g mercury, is
Options
A.0.059 V
B.0.0295 V
C.0.59 V
D.0.295 V
Solution
Net cell reaction: Zn – Hg(C1M) ? Zn – Hg(C2M)
$E_{cell} = 0 - \frac{0.059}{2}.\log\frac{C_{2}}{C_{1}} = - \frac{0.059}{2}\log\frac{1}{10} = 0.0295\text{ V}$
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