ElectrochemistryHard
Question
The equivalent conductivity (in Ω−1 cm2 eq−1) of 1.0 M – H2SO4 solution of specific conductance 2.6 × 10−1 cm−1, is
Options
A.1.3 × 102
B.6.5 × 101
C.1.3 × 10−1
D.2.6 × 102
Solution
$\Lambda_{eq} = \frac{k}{C} = \frac{2.6 \times 10^{- 1}}{(1 \times 2) \times 10^{- 3}} = 1.3 \times 10^{2}\text{oh}\text{m}^{- 1}\text{ c}\text{m}^{2}\text{ e}\text{q}^{- 1}$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Consider the reaction of extraction of gold from its ore:Au(s) + 2CN− (aq) + ¼ O2(g) + ½ H2O(l) → Au(CN)2−(aq) + OH−(aq)...Molar conductance of 0.1 M acetic acid is 7 ohm-1 cm2 mol-1. If the molar cond. of acetic acid at infinite dilution is 3...A lead storage cell is discharged which causes the H2SO4 electrolyte to change from a concentration of 40% by weight (de...An ammeter and a copper volta meter are connected in series in an electric circuit through which a constant direct curre...A cell Cu | Cu++ || Ag+ | Ag initially contains 2M Ag+ and 2M Cu++ ions in 1L electrolyte. The change in cell potential ...