ElectrochemistryMedium
Question
The equivalent conductivity (in Ω−1 cm2 eq−1) of 1.0 M – H2SO4 solution of specific conductance 2.6 × 10−1 cm−1, is
Options
A.1.3 × 102
B.6.5 × 101
C.1.3 × 10−1
D.2.6 × 102
Solution
$\Lambda_{eq} = \frac{k}{C} = \frac{2.6 \times 10^{- 1}}{(1 \times 2) \times 10^{- 3}} = 1.3 \times 10^{2}\text{oh}\text{m}^{- 1}\text{ c}\text{m}^{2}\text{ e}\text{q}^{- 1}$
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