SolutionMedium
Question
In the above problem, if the solution is cooled to −0.200°C, then how many grams of ice would separate?
Options
A.200
B.225
C.325
D.175
Solution
$\Delta T_{f} = K_{f}.m \Rightarrow 0.2 = 1.86 \times \frac{5/60}{m_{\text{solvent}}}$
$\Rightarrow M_{\text{solvent}} = 0.775\text{ Kg}$
∴ Mass of water separate as ice = 1 – 0.775 = 0.225 Kg
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