Solid StateHard
Question
A solid element (monoatomic) exists in cubic crystal. If its atomic radius is 1.0 Å and the ratio of packing fraction and density is 0.1 cm3/g, then the atomic mass of the element is (NA = 6 × 1023)
Options
A.8π
B.16π
C.80π
D.4π
Solution
$\frac{P.F.}{d} = \frac{V_{\text{Particle}}/V_{\text{Unitcell}}}{m_{\text{Particle}}/V_{\text{unitcell}}} = \frac{V_{\text{Particle}}}{m_{\text{Particle}}}$
Or, $0.1 = \frac{Z \times \frac{4}{3}\pi\left( 1.0 \times 10^{- 8} \right)^{3}}{Z \times M/6 \times 10^{23}} \Rightarrow M = 8\pi$
Create a free account to view solution
View Solution FreeMore Solid State Questions
A molecule A2B (Mw = 166.4) occupies triclinic lattice with a = 5, b = 8, and c = 4 .If the density of AB2 is 5.2 g cm-3...Which is the incorrect statement ?...In a body centered cubic cell (BCC), what is the value of lattice parameter, if the atomic radius is r:-...MgO exists in a rock salt type unit cell. Each Mg2+ ion will be in contact with...In a hypothetical solid, C atoms are found to form cubical close-packed lattice. A atoms occupy all tetrahedral voids an...