Solid StateHard
Question
Gold crystallizes with FCC lattice for which the side length of the unit cell is 5.0 Å. If the density of gold is 10.5 g/cm3, then the value of Avogadro number is (Au = 198)
Options
A.6.022 × 1023
B.6.034 × 1023
C.5.966 × 1023
D.6.022 × 1022
Solution
$d = \frac{Z.M}{N_{A}.V} \Rightarrow 10.5 = \frac{4 \times 198}{N_{A} \times \left( 5 \times 10^{- 8} \right)^{3}}$
$\Rightarrow N_{A} = 6.034 \times 10^{23}$
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