Ionic EquilibriumHard
Question
When glycinium hydrochloride (NH2CH2 COOH.HCl) is titrated against NaOH, pH at the first half equivalence point is 2.40 and the pH at second half equivalence point is 9.60. The pH at first equivalence point is
Options
A.2.40
B.9.60
C.6.00
D.7.20
Solution
$P^{K_{a1}} = 2.40\text{ and }\text{P}^{K_{a2}} = 9.60$
∴ Required pH = $\frac{1}{2}(2.40 + 9.60) = 6.00$
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