Ionic EquilibriumHard
Question
When glycinium hydrochloride (NH2CH2 COOH.HCl) is titrated against NaOH, pH at the first half equivalence point is 2.40 and the pH at second half equivalence point is 9.60. The pH at first equivalence point is
Options
A.2.40
B.9.60
C.6.00
D.7.20
Solution
$P^{K_{a1}} = 2.40\text{ and }\text{P}^{K_{a2}} = 9.60$
∴ Required pH = $\frac{1}{2}(2.40 + 9.60) = 6.00$
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
If 50 ml of 0.2 M KOH is added to 40 ml of 0.5 M HCOOH. the pH of the resulting solution is: (Ka = 1.8 × 10-4, log ...The solubility product of a salt having general formula MX2, in water is: 4 × 10-12. The concentration of M2+ ions ...The conjugate base of [AI(H2O)3(OH)3] is :...Match list I (Solutions of salts of ...) with list II (pH of the solution is given by) and select the correct answer usi...2.5 mL of M weak monoacidic base(Kb = 1 × 10-12 at 25o C) is titrated with M HCl in water at 25oC. The concentratio...