Ionic EquilibriumMedium
Question
n-coproic acid C5H11COOH found in coconut and palm oil is used in making artificial flavours and it has solubility in water equal to 11.6 g/L. The saturated solution has pH = 3.0. The Ka of acid is
Options
A.10−6
B.10−5
C.2 × 10–5
D.2 × 10–6
Solution
$\left\lbrack C_{5}H_{11}COOH \right\rbrack = \frac{11.6}{116} = 0.1\text{ M}$
Now, $\left\lbrack H^{+} \right\rbrack = \sqrt{K_{a}.C} \Rightarrow 10^{- 3} = \sqrt{K_{a} \times 0.1} \Rightarrow K_{a} = 10^{- 5}$
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