Redox and Equivalent ConceptHard

Question

Dichloroacetic acid (CHCl2CO2H) is oxidized to CO2, H2O and Cl2 by 1.2 equivalents of an oxidizing agent. Same amount of the acid can neutralize ‘X’ moles of NH3 to give ammonium dichloroacetate. The value of ‘X’ is

Options

A.0.4
B.0.3
C.0.2
D.0.1

Solution

$CHCl_{2}COOH + 3H_{2}O \rightarrow 2CO_{2} + H_{2}O + Cl_{2} + 6H^{+} + 6e^{-}$

$n_{eq}CHCl_{2}COOH = n_{eq}O.A. $$${\text{Or, n} \times \text{6=1.2} \Rightarrow \text{n=0.2} }{\text{Now, }\text{n}_{eq}CHCl_{2}COOH = n_{eq}NH_{3} }{\text{Or 0.2} \times \text{1=x} \times 1 \Rightarrow \text{x=0.2}}$$

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