Redox and Equivalent ConceptHard

Question

Which has the maximum number of equivalent per mole of the oxidant?

Options

A.Zn(s) + VO2+ (aq) → Zn2+ (aq) + V3+ (aq)
B.Ag(s) + NO2(aq) → Ag+ (aq) + NO2(g)
C.Mg(s) + V4+ (aq) → Mg2+ (aq) + V2+ (aq)
D.I(aq) + IO3(aq) → I3(aq)

Solution

neq = n × n-factor and n-factor is maximum for $IO_{3}^{-}\left( + 5\text{ to } - \frac{1}{3} \right)$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions