Redox and Equivalent ConceptHard
Question
Which has the maximum number of equivalent per mole of the oxidant?
Options
A.Zn(s) + VO2+ (aq) → Zn2+ (aq) + V3+ (aq)
B.Ag(s) + NO2−(aq) → Ag+ (aq) + NO2(g)
C.Mg(s) + V4+ (aq) → Mg2+ (aq) + V2+ (aq)
D.I−(aq) + IO3−(aq) → I3−(aq)
Solution
neq = n × n-factor and n-factor is maximum for $IO_{3}^{-}\left( + 5\text{ to } - \frac{1}{3} \right)$
Create a free account to view solution
View Solution FreeMore Redox and Equivalent Concept Questions
The oxidation numbers of C in HCN and HNC, respectively, are...KMnO4 reacts with oxalic acid according to the equation : 2MnO4- + 5C2O4- + 16H+ → 2Mn+2 + 10CO2 + 8H2O Here 20 ml...$Cr(OH)_{3} + ClO^{-} + OH^{-} \rightarrow ...... + Cl^{-} + H_{2}O$. The missing ion is...On heating in contact with tin, sulphurated hydrogen (V.D. = 17) is converted into hydrogen without change in volume. Th...The equivalent weight of ozone behaving as an oxidizing agent is...