Redox and Equivalent ConceptHard

Question

Molecular masses of NH3 and N2 are x1 and x2, respectively. In the reaction, N2 + 3H2 → 2NH3, their equivalent weights are y1 and y2. Then (y1 − y2) is

Options

A.$\left( \frac{2x_{1} - x_{2}}{6} \right)$
B.(x1 − x2)
C.(3x1 − x2)
D.(x1 − 3x2)

Solution

$\underset{\text{n-factor=6}}{N_{2}} + 3H_{2} \rightarrow 2NH_{3}\left( \text{No. of }\text{e}^{-}\text{ involved = 6} \right)$

$\therefore E_{NH_{3}} = \frac{x_{1}}{3}\text{ and }E_{N_{2}} = \frac{x_{2}}{6}$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions

Equivalent weight of H2SO4 in the reaction Mg + 2H2SO4 → MgSO4 + SO2 + 2H2O, is...A mixture of potassium chlorate, oxalic acid and sulphuric acid is heated. During the reaction which element undergoes m...KMnO4 reacts with oxalic acid according to the equation2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10 CO2 + 8 H2OHere, 20 mL...A volume of 50 ml of 0.1 M metal salt reacts completely with 25 ml of 0.1 M sodium sulphite. In the reaction, SO32− is o...A 0.5 g sample of KH2PO4 is titrated with 0.1 M NaOH. The volume of base required to do this is 25.0 ml. The reaction is...