Redox and Equivalent ConceptHard

Question

Molecular masses of NH3 and N2 are x1 and x2, respectively. In the reaction, N2 + 3H2 → 2NH3, their equivalent weights are y1 and y2. Then (y1 − y2) is

Options

A.$\left( \frac{2x_{1} - x_{2}}{6} \right)$
B.(x1 − x2)
C.(3x1 − x2)
D.(x1 − 3x2)

Solution

$\underset{\text{n-factor=6}}{N_{2}} + 3H_{2} \rightarrow 2NH_{3}\left( \text{No. of }\text{e}^{-}\text{ involved = 6} \right)$

$\therefore E_{NH_{3}} = \frac{x_{1}}{3}\text{ and }E_{N_{2}} = \frac{x_{2}}{6}$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions

Which ordering of compounds is according to the decreasing order of the oxidation state of nitrogen?...The oxidation state of bismuth in lithium bismuthate is...In the reaction, P4 + NaOH + H2O → PH3 + NaH2PO2, the equivalent weight of P4 is...The decomposition of KClO3 to KCl and O2 on heating is an example of...Which of the following condition favours the reduction of a metal oxide to metal?...