Redox and Equivalent ConceptHard

Question

Molecular masses of NH3 and N2 are x1 and x2, respectively. In the reaction, N2 + 3H2 → 2NH3, their equivalent weights are y1 and y2. Then (y1 − y2) is

Options

A.$\left( \frac{2x_{1} - x_{2}}{6} \right)$
B.(x1 − x2)
C.(3x1 − x2)
D.(x1 − 3x2)

Solution

$\underset{\text{n-factor=6}}{N_{2}} + 3H_{2} \rightarrow 2NH_{3}\left( \text{No. of }\text{e}^{-}\text{ involved = 6} \right)$

$\therefore E_{NH_{3}} = \frac{x_{1}}{3}\text{ and }E_{N_{2}} = \frac{x_{2}}{6}$

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