Redox and Equivalent ConceptHard

Question

RH2 (ion exchange resin) can replace Ca2+ in hard water as follows. RH2 + Ca2+ → RCa + 2H+.

One litre of hard water after passing through RH2 has pH = 2. Hence, hardness in ppm of Ca2+ is

Options

A.200
B.100
C.50
D.125

Solution

$\left( Ca^{2 +} \right) = \frac{10^{2}}{2} = 5 \times 10^{- 3}M$

∴ Hardness = $\left( \frac{5 \times 10^{- 3}}{1000} \times 10^{6} \right) \times 40 = 200\text{ ppm}$

Create a free account to view solution

View Solution Free
Topic: Redox and Equivalent Concept·Practice all Redox and Equivalent Concept questions

More Redox and Equivalent Concept Questions

Equivalent weight of H2SO4 in the reaction Mg + 2H2SO4 → MgSO4 + SO2 + 2H2O, is...$Cr(OH)_{3} + ClO^{-} + OH^{-} \rightarrow ...... + Cl^{-} + H_{2}O$. The missing ion is...Which of the following statement(s) is/are true regarding the change CN− → CNO−?...In which of the folowing compounds, nitrogen exhibits highest oxidation state ?...KMnO4 reacts with oxalic acid according to the equation2MnO4- + 5C2O42- + 16H+ → 2Mn2+ + 10 CO2 + 8 H2OHere, 20 mL...