Redox and Equivalent ConceptMedium
Question
RH2 (ion exchange resin) can replace Ca2+ in hard water as follows. RH2 + Ca2+ → RCa + 2H+.
One litre of hard water after passing through RH2 has pH = 2. Hence, hardness in ppm of Ca2+ is
Options
A.200
B.100
C.50
D.125
Solution
$\left( Ca^{2 +} \right) = \frac{10^{2}}{2} = 5 \times 10^{- 3}M$
∴ Hardness = $\left( \frac{5 \times 10^{- 3}}{1000} \times 10^{6} \right) \times 40 = 200\text{ ppm}$
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