Mole ConceptHard
Question
A mixture of propane and benzene is burnt completely in excess of oxygen at 110o C. It results in the production of equal volumes of CO2(g) and steam (measured under identical pressure and temperature). Which of the following is correct regarding the original mixture?
Options
A.The mole ratio of propane and benzene is 3: 1.
B.The mass ratio of propane and benzene is 22: 13.
C.The mole ratio of carbon and hydrogen atoms is 1: 2.
D.The mass ratio of carbon and hydrogen atoms is 6: 1.
Solution
C3H8 + 5O2 → 3CO2 + 4H2O(g)
x mole 3x mole 4x mole
C6H6 + $\frac{15}{2}$O2 → 6CO2 + 3H2O(g)
y mole 6y mole 3y mole
From question,
3x + 6y = 4x +3y ⇒ x: y = 3: 1 and nC: nH = (3x + 6y): (8x + 6y) = 1: 2
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
100 mL of 0.06 M Ca(NO3)2 is added to 50 mL of 0.06 M Na2C2O4. After the reaction is complete....When a sample of hydrogen fluoride is cooled to 303 K, most of the molecules undergo dimerization. If the vapour density...Which of the following statement is not true about H2O molecule :-...A definite volume of ammonia gas is passed through a series of electric sparks by which the volume becomes 90 ml. On was...For the given reaction;$${CaCO}_{3} + 2HCl \rightarrow {CaCl}_{2} + H_{2}O + {CO}_{2} $$If $90\text{ }g{CaCO}_{3}$ is ad...