A quantity of 2.3 g of a mixture of NO2 and N2O4 has a pressure of 0.82 atm, at temperature TK in a

Question

A quantity of 2.3 g of a mixture of NO2 and N2O4 has a pressure of 0.82 atm, at temperature TK in a container of volume V litres such that the ratio, T: V is 300: 1 in magnitude. What is the degree of dissociation of N2O4?

Accepted Answer

$M = \frac{WRT}{PV} = \frac{2.3 	imes 0.082}{0.82} 	imes \frac{300}{1} = 69$Now, $\alpha = \frac{M_{o} - M}{(n - 1).M} = \frac{92 - 69}{(2 - 1) 	imes 69} = 0.33$

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