Mole ConceptMedium
Question
A compound having the empirical formula, C3H4O has a molecular weight of 170 ± 5. The molecular formula of the compound is
Options
A.C3H4O
B.C6H8O2
C.C6H12O3
D.C9H12O3
Solution
$n = \frac{170 \pm 5}{12 \times 3 + 4 + 16} \approx 3$
⇒ Molecular formula = (C3H4O)3 = C=H12O3
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