Mole ConceptMedium
Question
The mass of CO2 that must be mixed with 20 g of oxygen such that 27 ml of a sample of the resulting mixture would contain equal number of molecules of each gas, is
Options
A.13.75 g
B.27.50 g
C.41.25 g
D.55 g
Solution
$\frac{w}{44} = \frac{20}{32} \Rightarrow w = 27.50g$
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