Mole ConceptHard
Question
The mass of CO2 that must be mixed with 20 g of oxygen such that 27 ml of a sample of the resulting mixture would contain equal number of molecules of each gas, is
Options
A.13.75 g
B.27.50 g
C.41.25 g
D.55 g
Solution
$\frac{w}{44} = \frac{20}{32} \Rightarrow w = 27.50g$
Create a free account to view solution
View Solution FreeMore Mole Concept Questions
The density of 3M sodium thiosulphate is 1.25 g/ml. Identify the correct statements among the following :...The boiling point of 0.2 mol kg-1 solution of X in water is greater than equimolal solution of Y in water. Which one of ...In a textile mill, a double effect evaporator system concentrates weak liquor containing 4% (by mass) caustic soda to pr...Mole fraction of the solute in a 1.00 molal aqueous solution is...14.0 g of calcium metal is allowed to react with excess HCl at 1.0 atm pressure and 273 K .Which of the following statem...