Atomic StructureEasy

Question

Suppose the mass of electron is decreased by 25%. How will it a­ffect the Rydberg constant?

Options

A.It remains unchanged.
B.It becomes one-fourth.
C.It reduces to 75% of its original value.
D.It is doubled.

Solution

$R = \frac{2\pi^{2}me^{4}}{\left( 4\pi\varepsilon_{o} \right)^{2}h^{3}c} \Rightarrow R \propto m$

Here, m becomes $\left( m - \frac{m}{4} = \frac{3m}{4} \right)$, then R becomes $\frac{3}{4}R$

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