Atomic StructureHard

Question

Suppose the mass of electron is decreased by 25%. How will it a­ffect the Rydberg constant?

Options

A.It remains unchanged.
B.It becomes one-fourth.
C.It reduces to 75% of its original value.
D.It is doubled.

Solution

$R = \frac{2\pi^{2}me^{4}}{\left( 4\pi\varepsilon_{o} \right)^{2}h^{3}c} \Rightarrow R \propto m$

Here, m becomes $\left( m - \frac{m}{4} = \frac{3m}{4} \right)$, then R becomes $\frac{3}{4}R$

Create a free account to view solution

View Solution Free
Topic: Atomic Structure·Practice all Atomic Structure questions

More Atomic Structure Questions

Ionisation energy of Cl- is 349 kJ mol-1. The electron gain enthalpy of chlorine would be :-...An α-particle has initial kinetic energy of 25 eV and it is accelerated through the potential difference of 150 vol...If an electron has spin quantum number of + ½ and magnetic quantum number of –1, then it cannot be present in...The ratio of wavelengths of Kα-characteristic X-rays produced when iron (Z = 26) and scandium (Z = 21) are used as antic...In different resonating form of a molecule what should be identical :-...