Atomic StructureEasy
Question
Suppose that means were available for stripping 29 electrons from 30Zn in vapours of this metal. The ionization energy for the last electron is
Options
A.11.5 keV
B.12.24 keV
C.13.6 eV
D.408 eV
Solution
Required I.E. = 13.6 × 302 = 12240 eV
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