Atomic StructureHard

Question

The wave function of 1s orbital of H-atom is $\Psi = \frac{1}{\sqrt{\pi}}\left( \frac{1}{a_{0}} \right)^{3/2}e^{- r/a_{0}}$, where ao = Bohr's radius. The probability of finding the electrons at a distance ‘r’ from the nucleus is given by

Options

A.$\Psi = \Psi^{2}dr$
B.$\int_{}^{}{\Psi^{2}4\pi r^{2}dr}$
C.$\Psi^{2}4\pi r^{2}dr$
D.$\Psi.dV$

Solution

Theoretical

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