The radius of the hydrogen atom in its ground state is 5.3 × 10–11 m. After collision with an electr

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The radius of the hydrogen atom in its ground state is 5.3 × 10–11 m. After collision with an electron it is found to have a radius of 21.2 × 10–11m. The principal quantum number of final state of the atom is

Accepted Answer

$r_{n} = r_{1} 	imes n^{2} \Rightarrow 21.2 	imes 10^{- 11} = 5.3 	imes 10^{- 11} 	imes n^{2} \Rightarrow n = 2$

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