Current Electricity and Electrical InstrumentHard

Question

A capacitor with charge Q on it is connected to an inductor L as shown in diagram at t = 0. When the switch is flipped from position 1 to 2, the current in the circuit is observed to be at half of its maximum value. Then : -
         

Options

A.Charge on capacitor at the time was
B.Charge on capacitor at that time was
C.Total energy lost is
D.Total energy lost is

Solution

= H ⇒ q =
∴ Energy in inductor

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