Math miscellaneousHard
Question
The largest value of positive integer k for which (xk + 1) divides (1 + x + x2 + .......+x127), is divisible by -
Options
A.8
B.16
C.32
D.64
Solution
We have
1 + x + x2 + .......+x127 =
=
= (x64 + 1) (1 + x +......+x63)
⇒ k = 64
1 + x + x2 + .......+x127 =
=
= (x64 + 1) (1 + x +......+x63)
⇒ k = 64
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