Math miscellaneousHard
Question
The largest value of positive integer k for which (xk + 1) divides (1 + x + x2 + .......+x127), is divisible by -
Options
A.8
B.16
C.32
D.64
Solution
We have
1 + x + x2 + .......+x127 =
=
= (x64 + 1) (1 + x +......+x63)
⇒ k = 64
1 + x + x2 + .......+x127 =
=
= (x64 + 1) (1 + x +......+x63)
⇒ k = 64
Create a free account to view solution
View Solution FreeMore Math miscellaneous Questions
If a, b, c are non-zero real numbers and if the equations (a - 1)x = y + z, (b - 1)y = z + x, (c - 1) z = x + y has a no...A body weighing 13 kg is suspended by two strings 5 m and 12 m long, their other ends being fastened to the extremities ...The integral is equal to...The point of lines represented by 3ax2 + 5xy + (a2 - 2)y2 = 0 and perpendicular to each other for...Let f(x) Then which one of the following is true?...