Work, Power and EnergyMedium
Question
In the given figure a ball of mass m is connected to an elastic spring of force constant K = mg/L through an inextensible string as shown. Now the ball is released from rest.
Options
A.The maximum velocity of mass m during fall is 
B.The maximum velocity of mass m during fall is 
C.The maximum potential energy stored in the spring during the fall is mgL [2 + √3]
D.The maximum potential energy stored in the spring during the fall is mgL [3 + √2]
Solution
Using energy conservation between initial moment and equilibrium moment when T = mg.
× L2 + 
mv2 = mg × 2L
V =
If ball falls a maximum distance of L + x.
mg(L + x) =
x2
x = L(1 + √3)
∴ PEmax = mgL(2 + √3)
× L2 + mv2 = mg × 2LV =
If ball falls a maximum distance of L + x.
mg(L + x) =
x2x = L(1 + √3)
∴ PEmax = mgL(2 + √3)
Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
Consider a drop of rain water having mass 1 g falling from a height of 1 km. It hits the ground with a speed of 50 m/s. ...The spring constant of two springs are K1 and K2 respectively springs are stretch up to that limit when potential energy...If a spring extends by x on loading then energy stored by the spring is :- (T is tension in the spring)If a spring exten...A constant force F is applied to a body of mass m moving with initial velocity u. If after the body undergoes a displace...An ideal spring with spring constant k is hung from the ceiling and a block of mass M is attached to its lower end. The ...