Area under the curveHard

Question

One vertex of the triangle of maximum area that can be inscribed in the curve |z - 2i| = 2 is 2 + 2i, remaining vertices can be -

Options

A.-1+ i(2 + √3)
B.-1- i(2 + √3)
C.-1 + i(2 - √3)
D.-1 - i(2 - √3)

Solution

           
Clearly, the triangle is equilateral. using rotation concept

z1 - 2i = [(2+ 2i) - 2i].e
∴ ahnd z - 2i = [(2 + 2i) - 2i].e
∴ z2 = - 1 + i(2 + √), z2 = - 1+ i(2 - √3)

Create a free account to view solution

View Solution Free
Topic: Area under the curve·Practice all Area under the curve questions

More Area under the curve Questions

Area of the region bounded by the curves y = ex , y = e−x and the straight line y = 2 is-...The area bounded between the curve x2 + y2 = 9 and lines y = 3/2, y = 3 and x = 0 is-...The common area of the curves y = √x and x = √y is-...Consider the following regions in the plane :R1 = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1} and R2 = {(...The area between the curve y = sec x and y-axis when 1 ≤ y ≤ 2 is-...