Trigonometric EquationHard
Question
Let f(n) = tan-1
+ tan-1
+ tan-1
+ .... n terms, then
f(n) is -
Options
A.less than
but greater than
B.less than
C.greater than 
D.equal to 
Solution
Tn = tan-1 
= tan-1
Tn = tan-1 ((n + 1) (n + 2)) - tan-1(n(n + 1))
∑ Tn = tan-1(n + 1)(n + 2) - tan-12
f(n) =
- tan-1 2 = tan-1
√2 - 1 <
⇒ tan-1 (√2 - 1) < tan-1
tan-1
> 
= tan-1
Tn = tan-1 ((n + 1) (n + 2)) - tan-1(n(n + 1))
∑ Tn = tan-1(n + 1)(n + 2) - tan-12
√2 - 1 <
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