Basic Maths and Units and DimensionsHard
Question
The equation of the circle passing through the foci of the ellipse
and having centre at (0, 3) is :
and having centre at (0, 3) is : Options
A. x2 + y2 - 6y - 7 = 0
B. x2 + y2 - 6y + 7 = 0
C. x2 + y2 - 6y - 5 = 0
D. x2 + y2 - 6y + 5 = 0
Solution


foci

centre of circle is (0, 3)
x2 + y2 - 6y + c = 0
passes through (√7, 0)
7 + 0 - 0 + c = 0
c = -7
So x2 + y2 - 6y - 7 = 0
Create a free account to view solution
View Solution FreeTopic: Basic Maths and Units and Dimensions·Practice all Basic Maths and Units and Dimensions questions
More Basic Maths and Units and Dimensions Questions
If the rate of emission of radiation and the rate of absorption by surface of a body are same then the temperature of bo...In the given circuit, charge Q2 on the 2μF capacitor changes as C is varied from 1μF to 3μF. Q2 as a func...Three charges q, 2q and 4q are placed on straight line at equal distances, then ratio of the force exerted by q on 4q an...The x and y coordinates of the particle at any time are x = 5t - 2t2 and y = 10t respectively, where x and y are in mete...An ideal gas is expanding such that PT2 = constant. The coefficient of volume expansion of the gas is...