Application of DerivativeHard
Question
Slope of common tangent to y2 = 4x and x2 + 4y2 = 8 is
Options
A.5/4
B.5/2
C.1/2
D.9/2
Solution
y = mx + 
y = mx ±
8m2 + 2 =
8m4 + 2m2 - 1 = 0(2m2 + 1) (4m2 - 1) = 0
y = mx ±
8m2 + 2 =
8m4 + 2m2 - 1 = 0(2m2 + 1) (4m2 - 1) = 0
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