Application of DerivativeMedium

Question

Slope of common tangent to y² = 4x and x² + 4y² = 8 is

Options

A.5/4

B.5/2

C.1/2

D.9/2

Solution

y = mx +
y = mx ±
8m² + 2 =
8m⁴ + 2m² - 1 = 0(2m² + 1) (4m² - 1) = 0

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