Physics miscellaneousHard
Question
The number of values of k, for which the system of equations :
(k + 1)x + 8y = 4k
kx + (k + 3)y = 3k - 1
has no solution, is :
(k + 1)x + 8y = 4k
kx + (k + 3)y = 3k - 1
has no solution, is :
Options
A.infinite
B.1
C.2
D.3
Solution
(1) = (2)
⇒k2 - 4k + 3 = 0
k = 1, 3
for k = 1, (2) = (3)
for k = 3, (2) ≠ (3)
k = 3
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