Current Electricity and Electrical InstrumentMedium
Question
An electric circuit consists of a battery emf E = 110 V, and internal resistance is 5Ω and two resistors connected in parallel to the source as shown in figure. Determine the value of R so that maximum power get dissipated in resistance R.
Options
A.50/11
B.50/12
C.50
D.50/13
Solution
Current in resistance R is
Power =
× R
For maximum power
= 0 ⇒ R = 
Power =
× R For maximum power
= 0 ⇒ R = Create a free account to view solution
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