Basic Maths and Units and DimensionsHard
Question
In the figure shown, C1 = 11μF and C2 = μF, then at steady state:
Options
A.the potential difference across C1 is 5V
B.the potential difference across C2 is 5V
C.the potential difference between points a and b is -4V
D.the potential difference between the terminals of 15 V battery is 9V
Solution
At steady state I(3) + I(2) = 15 ⇒ I = 3
KVL C → D → E → a → b → C
Vc - I (3) +
- 7 + 
= VC
+ = 7 + 3 × 3 = 16 ⇒ q = 55 μC.
Now KVL for a → b
Va - 7 + = Vb ⇒ Va - Vb = 7 - = 7 - 
= - 4V
Potential difference across C1 :
⇒ P.d. across C2 : 
= 11V
Potential difference across terminal = 15 - I(2) = 15 - 3 × 2 = 9V
KVL C → D → E → a → b → C
Vc - I (3) +
- 7 + = VC + = 7 + 3 × 3 = 16 ⇒ q = 55 μC.Now KVL for a → b
Va - 7 +
= Vb ⇒ Va - Vb = 7 - = 7 - = - 4VPotential difference across C1 :
⇒ P.d. across C2 : = 11VPotential difference across terminal = 15 - I(2) = 15 - 3 × 2 = 9V
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