Permutation and CombinationHard
Question
The number of ways in which 3 different red, 3 different white and 3 different black balls can be arranged in a line such that any three consecutive balls in any arrangement are of different colours -
Options
A.6(3!)2
B.54(3!)2
C.27(3!)2
D.24(3!)2
Solution
RBW can be arranged in 3! = 6 ways for one such way
∴ Total ways = (3! × 3! × 3!) × 3! = 36(3!)2
∴ Total ways = (3! × 3! × 3!) × 3! = 36(3!)2
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