p-Block elementsHard

Question

Which one of the following in the correct decreasing order of boiling point ?

Options

A.H2Te > H2O > H2Se > H2S
B.H2O > H2S > H2Se > H2Te
C.H2Te > H2Se > H2S > H2O
D.H2O > H2Te > H2Se > H2S

Solution

Among the hydrides of group 16 elements, boiling point of H2O is higher than H2S (differecein biling points of H2O and H2S is around 200oC) because of strong intermolecular hydrogen bonding. After the decrease in boiling point from H2O to H2S, from H2S to H2Te, it increases due to increase in size of the atoms from S to Te which in creases the magnitude of van der Waal’s forces among the molecules. So the correct order point is
H2O > H2Te > H2Se > H2S

Create a free account to view solution

View Solution Free
Topic: p-Block elements·Practice all p-Block elements questions

More p-Block elements Questions