ThermodynamicsHard
Question
A gas expands isothermally against a constant external pressure of 1 atm from a volume of 10dm3 to a volume of 20dm3. It absorbs 300J of thermal energy from its surrounding. The ᐃU is :
Options
A.- 312 J
B.+123 J
C.- 213 J
D.+ 231 J
Solution
W = -
PdV = - P(V2 - V2)
W = - (1atm) (20 - 10) = 10 dm3atm.
= - 10 dm3 ×
= - 1013 J
According to Ist law of thermodynamics, ᐃU = q + W = 800J + (-1013J) = - 213J
PdV = - P(V2 - V2)W = - (1atm) (20 - 10) = 10 dm3atm.
= - 10 dm3 ×
= - 1013 JAccording to Ist law of thermodynamics, ᐃU = q + W = 800J + (-1013J) = - 213J
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
For the cell, Mn(s)|Mn(aq)+2(0.4M)||Sn(aq)+2(0.04)|Sn(s), Calculate free energy change (ᐃG) at 298 K. Given : EoMn...Equal volumes of two monoatomic gases, A and B, at same temperature and pressure are mixed. The ratio of specific heats ...The difference between heats of reaction at constant pressure and constant volume for the reaction 2C6H6(l) + 1502(g) &#...Calculate ᐃfGo for (NH4CI, s) at 310 K.Given : ᐃfHo (NH4CI, s) = - 314.5 kJ/mol; ᐃrCp = 0SoN2(g) = 192...In any natural process :-...