ThermodynamicsHard
Question
A gas expands isothermally against a constant external pressure of 1 atm from a volume of 10dm3 to a volume of 20dm3. It absorbs 300J of thermal energy from its surrounding. The ᐃU is :
Options
A.- 312 J
B.+123 J
C.- 213 J
D.+ 231 J
Solution
W = - 
PdV = - P(V2 - V2)
W = - (1atm) (20 - 10) = 10 dm3atm.
= - 10 dm3 ×
= - 1013 J
According to Ist law of thermodynamics, ᐃU = q + W = 800J + (-1013J) = - 213J
PdV = - P(V2 - V2)W = - (1atm) (20 - 10) = 10 dm3atm.
= - 10 dm3 ×
= - 1013 JAccording to Ist law of thermodynamics, ᐃU = q + W = 800J + (-1013J) = - 213J
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