Geometrical OpticsHard
Question
A lens of focal length ′f′ is placed in between an object and screen at a distance ′D′. The lens forms two real images of object on the screen for two of its different positions, a distance ′x′ apart. The two real images have magnifications m1 and m2 respectively (m1 > m2). Then :-
Options
A.f = 
B.m1m2 = 1
C.f = 
D.D ≥ 4f
Solution
For convex lens
m1 - m2 = 
.......(ii)
.......(i) x = v - u .......(iii)
Using (i) & (ii) & (iii)
f =
m1 - m2 = .......(ii) .......(i) x = v - u .......(iii)Using (i) & (ii) & (iii)
f =
Create a free account to view solution
View Solution FreeMore Geometrical Optics Questions
An astronomical telescope has a large aperture to...A convex lens forms an image of an object on a screen . The height of the image is 9 cm. The lens is now displaced until...The minimum distance between the object and its real image for concave mirror is...The focal length of convex lens is 2.5 cm. Its magnifying power for minimum distance of distinct vision will be -...For the given incident ray as shown in figure, the condition of total internal refraction of this ray the minimum refrac...