Geometrical OpticsHardBloom L3
Question
A lens of focal length ′f′ is placed in between an object and screen at a distance ′D′. The lens forms two real images of object on the screen for two of its different positions, a distance ′x′ apart. The two real images have magnifications m1 and m2 respectively (m1 > m2). Then :-
Options
A.f = 
B.m1m2 = 1
C.f = 
D.D ≥ 4f
Solution
For convex lens
m1 - m2 = 
.......(ii)
.......(i) x = v - u .......(iii)
Using (i) & (ii) & (iii)
f =
m1 - m2 = .......(ii) .......(i) x = v - u .......(iii)Using (i) & (ii) & (iii)
f =
Create a free account to view solution
View Solution FreeMore Geometrical Optics Questions
A prism of angle $75^{\circ}$ and refractive index $\sqrt{3}$ is coated with thin film of refractive index 1.5 only at t...Consider the situation shown in figure. Water is filled in a beaker up to a height of 10 cm. A plane mirror is fixed at ......For a given lens the magnification was found to be twice as large as when the object was0.15 m distant from it as when t...If two mirrors are kept at 60o to each other, then the number of images formed by them is...