Math miscellaneousHard
Question
If | x2 - x - 6 | = x + 2, then number of positive integral solutions of equation is :
Options
A.1
B.2
C.4
D.8
Solution
Take two cases,
i.e., x2 - x - 6 ≥ 0
⇒ (x - 3) (x + 2) ≥ 0 and x2 - x - 6 < 0
⇒ (x - 3) (x + 2) < 0
Then we have two positive integral values of x i.e. 2, 4.
i.e., x2 - x - 6 ≥ 0
⇒ (x - 3) (x + 2) ≥ 0 and x2 - x - 6 < 0
⇒ (x - 3) (x + 2) < 0
Then we have two positive integral values of x i.e. 2, 4.
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