Magnetic field due to currentHard
Question
A particle of charge +q and mass m moving under the influence of uniform electric field 
and uniform magnetic field 
follows a trajectory from P to Q as shown in figure. The velocities at P and Q are 
and 
respectively. Choose the CORRECT statement(s).
and uniform magnetic field follows a trajectory from P to Q as shown in figure. The velocities at P and Q are and respectively. Choose the CORRECT statement(s).Options
A.E = 
B.Rate of work done by electric field at P = 
C.Rate of work done by electric field at P is zero
D.Rate of work done by both fields at Q is zero
Solution
W = ᐃK.E.
qE(2a) =
m [(2v)2 - v2]
E =
Rate of workdone at P =
= qE vcos0o = 
Rate of workdone at Q = = qE 2vcos 90o = 0
qE(2a) =
m [(2v)2 - v2]E =
Rate of workdone at P =
= qE vcos0o = Rate of workdone at Q =
= qE 2vcos 90o = 0Create a free account to view solution
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