Fluid MechanicsHard
Question
If liquefied oxygen at 1 atmospheric pressure is heated from 50K to 300 K by supplying heat at constant constant rate. the graph of temperature vs time will be
Options
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Solution
Q = mcᐃT
Q = mv(T - T0) ....(i)
Q = Kt whereas K is heating rate
∴ from 50 to boiling temprature, T increases linearly.
At vaporization, equation is Q = mL
so, temperature remains constant till vaporisation is complete
After that, again Eqn (i) is followedand temperature increase linearly
Q = mv(T - T0) ....(i)
Q = Kt whereas K is heating rate
∴ from 50 to boiling temprature, T increases linearly.
At vaporization, equation is Q = mL
so, temperature remains constant till vaporisation is complete
After that, again Eqn (i) is followedand temperature increase linearly
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