Work, Power and EnergyHard
Question
For 100% modulation (AM), the useful part of the total power radiated is
Options
A.
of the total power
of the total powerB.
of the total power
of the total powerC.
of the total power
of the total powerD.
of the total power
of the total powerSolution
100% modulation ⇒ Ma = 1
⇒ Useful power =
(total power radiated)
⇒ Useful power =
(total power radiated)Create a free account to view solution
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