Sound WavesMedium
Question
When two tuning forks (fork 1and fork 2)are sounded simultaneously, 4beats per second are heard. Now some type is attached on the prong of the fork2. When the tuning forks are sounded again, 6 beats per second are heard. If the frequency of fork 1is 200 Hz, then what was the original frequency of frank 2?
Options
A.202 Hz
B.200 Hz
C.204Hz
D.196Hz
Solution
Frequency of fork l = 200 Hz = no
No. of beats heard when fork 2 is sounded with fork l ᐃn = 4
Now we know that if on loading (attaching tape)an unkown fork, the beat frequency increase (frons 4to 6 in this case) then the frequencfy of the unknown fork 2 is given by n = no = ᐃn = 200 - 4 = 196 Hz
No. of beats heard when fork 2 is sounded with fork l ᐃn = 4
Now we know that if on loading (attaching tape)an unkown fork, the beat frequency increase (frons 4to 6 in this case) then the frequencfy of the unknown fork 2 is given by n = no = ᐃn = 200 - 4 = 196 Hz
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