Rotational MotionMedium
Question
A disc is rolling (without slipping) on na horizontal surface. C is its center and Q and P are two points equidistant from C. Let Vp′ Vq′ and Vc′ be the magnitude of velocities of point P,Q and C respectively, then
Options
A.VQ > VC > VP
B.VQ < VC < VP
C.VQ = VP VC = 
VP
VPD.VQ < VC > VC
Solution
From fig .(I),we have OC = r (radius)
Therefore, v = r
Since, ω = Constant therefore v ∝ r
Now, form fig (II), It is clear that the distance, OP < OC < OQ ⇒ VPVCVQ or VQVCVP
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