Current Electricity and Electrical InstrumentHard

Question

For the circuit shown in the fig., the current thruouh the inductor is 0.9 A while the current through the condenser is 0.4. Then
     

Options

A.current drawn from grnerator I = 1.13 A
B.ω = 1/(1.5LC)
C.I = 0.5 A
D.I = 0.6 A

Solution

The current drawn by inductor and capcitor will be in opposite phase. Hence netcurrent drawn from generator
= IL - IC = 0.9 - 0.4 = 0.5amp.

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